Answer:
the perimeter of ΔABC is 32in
Explanation:
We know that intersection point of the angle bisectors refers to the incenter of the triangle,.
Given tmthe radius of 4inch for the centre of the incircle.
One of the properties of the incircle is that the distances (d) from vertex C to the nearest touchpoints are equal and have the value
In an incircle , the distances (d) along vertex C and touchpoints have equal value and can be expressed as
d = 1/2(a +b -c)
And a, b, c represent lengths of the sides
We were given the hypotenuse (c) as 12 in, with the radius of 4inch for the
distance from the right-angle vertex C to the incircle touchpoints .
We can determine the sum a+b as
4 = (1/2)(a+b -12) .
4/(1/2)= (a+b -12)
8= (a+b -12)
20=a+b
Which is the addition of length of the two legs of the triangle.
We can determine the perimeter which is the addition of the leg lengths as well as the hypotenuse length.
perimeter = 20 in + 12 in = 32 in
Therefore, the perimeter of ΔABC is 32in