Question

Write an equation for a line perpendicular to y = − 5 x + 5 and passing through the point (5,5)

Answer 1

y=0.2x+4 or y=1/5 x+4.

Explanation:

When one line is perpendicular to another, you have to find the opposite reciprocal for the slope of the given equation.

For instance, if you have the number 5, the reciprocal of 5 is 1/5 or 0.2. The opposite of positive is negative. Therefore, it is -0.2.

Therefore, if the slope of the first equation is -5, the slope for the next equation is 1/5. Reciprocal of -5 is -1/5. The opposite of -1/5 is positive 1/5. Or, the opposite of negative is positive. Therefore, it would be 1/5x.

However, we are not done.

Since we are given that the line passes through the point (5,5), we need to find the y-intercept of this equation.

The formula for slope-intercept is y=mx+b.

M is your slope

B is your y-intercept.

We can find the y-intercept by actually plugging in the point (5,5) into the new equation.

5=0.2(5)+b.

5 is x and 5 is also y.

(x,y).

Simplify the equation by multiplying 0.2 times 5. That is equal to 1.

We now have 5=1+b.

Isolate for the letter "b" by subtracting 1 from both sides.

1-1 is 0.

5-1 is 4.

Therefore, b=4.

Finally, we can plug in the y-intercept into the new equation.

y=0.2 or 1/5x+4.

I hope this helps! I also hope you have a great rest of your day!

Answer 2

The answer is

`y = (1)/(5) x + 4`

Explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the line perpendicular to

y = -5x + 5 we must first find the slope of

Comparing with the general equation above

Slope = - 5

The slope of the perpendicular line is the negative inverse of the slope of the original line

Slope of perpendicular line = 1/5

Equation of the line using point (5,5) and slope 1/5 is

`y - 5 = (1)/(5) (x - 5)`

`y - 5 = (1)/(5) x - 1`

`y = (1)/(5) x - 1 + 5`

We have the final answer as

`y = (1)/(5) x + 4`

Hope this helps you