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Can you help me learn how to solve problems like these? I need to know the answer, but I also need to know how to do it because this isn't all of them.


(1)/(p-2) / (4p^2)/(p^2+p-6)

(6n)/(3n+2) - (2)/(2n-2)

(2x)/(3x^2+18x) + (3)/(2)

User Artm
by
5.0k points

2 Answers

3 votes


((1)/(p-2))/((4p^2)/(p^2+p-6))=\\\\\\(1)/(p-2)\cdot(p^2+p-6)/(4p^2)=\\\\(1)/(p-2)\cdot(p^2+3p-2p-6)/(4p^2)=\\\\(1)/(p-2)\cdot(p(p+3)-2(p+3))/(4p^2)=\\\\(1)/(p-2)\cdot((p-2)(p+3))/(4p^2)=\\\\(p+3)/(4p^2)

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(6n)/(3n+2)-(2)/(2n-2)=\\\\(6n(2n-2))/((3n+2)(2n-2))-(2(3n+2))/((3n+2)(2n-2))=\\\\(12n^2-12n-(6n+4))/(6n^2-6n+4n-4)=\\\\(12n^2-12n-6n-4)/(6n^2-2n-4)=\\\\(12n^2-18n-4)/(6n^2-2n-4)=\\\\(2(6n^2-9n-2))/(2(3n^2-n-2))=\\\\(6n^2-9n-2)/(3n^2-n-2)

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(2x)/(3x^2+18x)+(3)/(2)=\\\\(2)/(3x+18)+(3)/(2)=\\\\(2\cdot2)/(2(3x+18))+(3(3x+18))/(2(3x+18))=\\\\(4+9x+54)/(6x+36)=\\\\(9x+58)/(6x+36)

User Janeen
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5.2k points
0 votes

Answer:

p^3−10p^2+1

—————— We find roots of zeros F(p) = p^3 - 10p^2 + 1 and see there

p^2 are no rational roots

Explanation:

p^2

Simplify ——

p^2

1.1 Canceling out p^2 as it appears on both sides of the fraction line

Equation at the end of step 1

:1

((————-(4•1))+p)-6

(p^2)

STEP 2: working left to right

1

Simplify ——

p^2

Equation at the end of step 2:

1 /p^2 ((—— - 4) + p) - 6

STEP 3:

Rewriting the whole as an Equivalent Fraction

3.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using p^2 as the denominator :

4 4 • p^2

4 = — = ——————

1 p^2

Equivalent fraction

: The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

1 - (4 • p^2) 1 - 4p^2

———————————— = ———————

p^2 p^2

Equation at the end of step 3:

(1 - 4p^2)

(————————— + p) - 6

p^2

STEP 4:

Rewriting the whole as an Equivalent Fraction

4.1 Adding a whole to a fraction

Rewrite the whole as a fraction using p2 as the denominator :

p p • p^2

p = — = ——————

1 p^2

Trying to factor as a Difference of Squares:

4.2 Factoring: 1 - 4p^2

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 1 is the square of 1

Check : 4 is the square of 2

Check : p^2 is the square of p^1

Factorization is : (1 + 2p) • (1 - 2p)

Adding fractions that have a common denominator :

4.3 Adding up the two equivalent fractions

(2p+1) • (1-2p) + p • p^2 p^3 - 4p^2 + 1

———————————————————————— = ————————————

p^2 p^2

Equation at the end of step

4:

(p^3 - 4p^2 + 1)

—————————————— - 6

p^2

STEP 5:

Rewriting the whole as an Equivalent Fraction

5.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using p^2 as the denominator :

6 6 • p^2

6 = — = ——————

1 p^2

Polynomial Roots Calculator :

5.2 Find roots (zeroes) of : F(p) = p^3 - 4p^2 + 1

Polynomial Roots Calculator is a set of methods aimed at finding values of p for which F(p)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers p which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 1 and the Trailing Constant is 1.

The factor(s) are:

of the Leading Coefficient : 1

of the Trailing Constant : 1

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 -4.00

1 1 1.00 -2.00

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

5.3 Adding up the two equivalent fractions

(p3-4p2+1) - (6 • p2) p3 - 10p2 + 1

————————————————————— = —————————————

p2 p2

Polynomial Roots Calculator :

5.4 Find roots (zeroes) of : F(p) = p3 - 10p2 + 1

See theory in step 5.2

In this case, the Leading Coefficient is 1 and the Trailing Constant is 1.

The factor(s) are:

of the Leading Coefficient : 1

of the Trailing Constant : 1

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 -10.00

1 1 1.00 -8.00

Polynomial Roots Calculator found no rational roots

Final result :

p3 - 10p2 + 1

—————————————

p2

User Danger Veger
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