Answer:
(i) 0.32 (ii) 0.85
(iii) 0.3412 (iv) 0.20
(v) 0.29 (vi) 0.12
Explanation:
The data provided is as follows:
Race Smoker (S) Nonsmoker (N) Row Total
White(W) 290 560 850
Black(B) 30 120 150
Column Total 320 680 1,000
(i)
Compute the value of P (S) as follows:
![P(S)=(n(S))/(N)=(320)/(1000)=0.32](https://img.qammunity.org/2021/formulas/mathematics/college/qzw1fkbcnsxabcnrjclbjic3yjxwzofgme.png)
P (S) = 0.32.
(ii)
Compute the value of P (W) as follows:
![P(W)=(n(W))/(T)=(850)/(1000)=0.85](https://img.qammunity.org/2021/formulas/mathematics/college/j9lzskh1ynlqj6s2i7bhgf68uprchjxnwe.png)
P (W) = 0.85.
(iii)
Compute the value of P (S|W) as follows:
![P(S|W)=(n(S\cap W))/(n(W))=(290)/(850)=0.3412](https://img.qammunity.org/2021/formulas/mathematics/college/eua99sgdyhv5idip8kb2q5nswagqz9n1w1.png)
P (S|W) = 0.3412.
(iv)
Compute the value of P (S|B) as follows:
![P(S|B)=(n(S\cap B))/(n(B))=(30)/(150)=0.20](https://img.qammunity.org/2021/formulas/mathematics/college/p5um5ny9zc79286fjpfuiwnj5lrsmofduo.png)
P (S|W) = 0.20.
(v)
Compute the value of P (S∩W) as follows:
![P(S\cap W)=(n(S\cap W))/(T)=(290)/(1000)=0.29](https://img.qammunity.org/2021/formulas/mathematics/college/do6c22goqmm4hoh75l6e7mfxt8i3ss6c1s.png)
P (S∩W) = 0.29.
(vi)
Compute the value of P (N∩B) as follows:
![P(N\cap B)=(n(N\cap B))/(T)=(120)/(1000)=0.12](https://img.qammunity.org/2021/formulas/mathematics/college/8sjc8gwstuyv0zscr8gjoxgl5z71xa3jl1.png)
P (S∩W) = 0.12.