Question

If


`log_(x) \: a \: + log_(x) \: (1)/(a) = t`
what is the possible value of t?​

Answer 1

I’m pretty sure the answer is t=0

Answer 2

t= 0

Explanation:

Using the rules of logarithms

log x + log y = log(xy)

`log_(b)` 1 = 0

Given

`log_(x)` a +
`log_(x)`
`(1)/(a)` = t ,then

`log_(x)` (a ×
`(1)/(a)` ) = t

`log_(x)` 1 = t , thus

t = 0