Answer:
(A) 0.11
(B) 0.0526
(C) Related
(D) 0.28
Explanation:
The data provided is:
DC = event that a randomly selected driver is using a cell phone
TA = event that a randomly selected driver has a traffic accident
(A)
From the provided data:
P (DC) = 0.11
(B)
From the provided data:
P (TA) = 0.0526
(C)
To determine whether the events DC and TA are dependent, we need to show that:
![P(DC\cap TA)\\eq P(DC)* P(TA)](https://img.qammunity.org/2021/formulas/mathematics/college/a2qjhponamdu5ifvu6uq85l13o70mhs71b.png)
The value of P (DC ∩ TA) is,
![P(DC\cap TA)=P(DC|TA)\time P(TA)](https://img.qammunity.org/2021/formulas/mathematics/college/n62c88v81jqubcmnv9ulppvcfkqb8z1fns.png)
![=0.28* 0.0526\\=0.014728](https://img.qammunity.org/2021/formulas/mathematics/college/79f3rwn8aqiz2vcgwvcfy4iwn4uze063u3.png)
Now compute the value of P (DC) × P (TA) as follows:
![P (DC) * P (TA)=0.11* 0.0526=0.005786](https://img.qammunity.org/2021/formulas/mathematics/college/tupo22xe1wsqs7ajctep2g8or81a7g9t5p.png)
So,
![P(DC\cap TA)\\eq P(DC)* P(TA)](https://img.qammunity.org/2021/formulas/mathematics/college/a2qjhponamdu5ifvu6uq85l13o70mhs71b.png)
Thus, cell phone use while driving and traffic accidents are related.
(D)
The probability that the driver was distracted by a cell phone given that the driver has an accident is:
P (DC | TA) = 0.28