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What are the solutions to the system of equations? {y=2x2−8x+5y=x−2 (3.5, 0.5) and (1, −1) (7, 5) and (0.5, −1.5) (3.5, 1.5) and (1, −1) (3.5, 1.5) and (−1, −3)

1 Answer

4 votes

Answer:


(1,-1) and
(3.5,1.5)

Explanation:

Given


y = 2x^2 - 8x+5


y = x - 2

Required

Determine the solution

Substitute x - 2 for y in
y = 2x^2 - 8x+5


x - 2 = 2x^2 - 8x+5

Collect like terms


0 = 2x^2 - 8x - x + 5 + 2


0 = 2x^2 - 9x + 7

Expand the expression


0 = 2x^2 - 7x - 2x+ 7

Factorize


0 = x(2x - 7) -1(2x - 7)


0 = (x-1)(2x - 7)

Split the expression


x - 1 = 0 or
2x - 7 = 0

Solve for x in both cases


x = 1 or
2x = 7


x = 1 or
2x/2 = 7/2


x = 1 or
x = 3.5

Recall that


y = x - 2

When
x = 1


y = 1 -2


y = -1

When
x = 3.5


y = 3.5 - 2


y = 1.5

Hence, the solution is;


(1,-1) and
(3.5,1.5)

User Pierre Capo
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