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A club has 16 members, included Mary and Peter. If two representative are

randomly selected from those members, find the probability that
(d) Mary or Peter is chosen.​

1 Answer

0 votes

Answer:

12.5 percent; 2/16; 1/8

Explanation:

Peter and Mary make up 2 of the clubs members, so the probability that they are chosen is 2/16. This simplifies to 1/8, and in decimal form is .125. Therefore, the percentage form of the probability they are chosen is 12.5 percent.

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