Factorise the following using the Difference of Two Squares or Perfect Squares rule: a) (2x-2)^2 - (x+4)^2 b) (3x+4) (3x-4)

asked Oct 15, 2021 158k views

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2 votes

Answer:

Explanation:

Hello, please consider the following.

$(2x-2)^2 - (x+4)^2 \\\\=(2x-2-(x+4))(2x-2+x+4)\\\\=(2x-2-x-4)(3x+2)\\\\=\boxed{(x-6)(3x+2)}$

$(3x+4) (3x-4)\\\\=(3x)^2-4^2\\\\=\boxed{9x^2-16}$

Thank you.

JoCa answered Oct 21, 2021

by JoCa

4.9k points

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