Question

Plz hurry thank you!
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Answer 1

Greetings from Brasil...

According to the properties of the radiation:

X^(a/b) =
`\sqrt[b]{X^a}`

So

X^(2/3) =
`\sqrt[3]{X^2}`

And

Y^(-3/4) = 1/Y^(3/4)

so 1/Y^(-3/4) = Y^(3/4) =
`\sqrt[4]{Y^3}`

Then we get

`\sqrt[2]{X^3} .\sqrt[4]{Y^3}`