Question

Please Help ;-;" :Mr. Gordon’s science class is studying blood types. The table below shows the probability that a person living in the US has a particular blood type. ( Type 0=9/20) (Type A=41/100) (Type B=1/10) (Type AB=1/25) What is the probability that three students selected randomly from the class will have A, B, and AB blood, respectively? Explain how you would solve this problem.

Answer 1

A = 6.9%

B = 0.1%

AB = 1.6%

Explanation:

A=0.41=41/100

B=0.1=1/10

AB=0.25=1/25

41/100³ = 0.41³ = 0.069 = 6.9%

1/10³ = 0.1³ = 0.001 = 0.1%

1/25³= 0.25³ =0.016 = 1.6%

I did to the power of 3 because the equation just looks like this

41/100 x 41/100 x 4/100

this is because you are multiplying each number by the amount of students selected.