Question

A travel agent is booking trips for tourists who travel from New York to Chicago. Tourists have three choices for how to travel from New York to Chicago. They can take an airplane for $350, a bus for $150, or a train for $225. Once they arrive in Chicago, they can travel by van to their hotel for $60 or take a cab for $40. If each option is equally likely to occur, what is the probability that a tourist will spend more than $300 on these 2 legs of the trip?

Answer 1

List all the different combinations with total cost:

Airplane + van = 350 + 60 = $410

Airplane + cab = 350 + 40 = $390

Bus + van = 150 + 60 = $210

Bus + cab = 150 + 40 = $190

Train + van = 225 + 60 = $285

Train + cab = 225 + 40 = $265

There are 6 different combinations.

There are 2 that are more than $300

The probability would be quantity higher than 300 / total combinations.

Probability = 2/6 = 1/3