![\LARGE{ \boxed{ \red{ \rm{Answer}}}}](https://img.qammunity.org/2021/formulas/chemistry/middle-school/s5tij4ye84k4nuuw7q3bt780qk1yl7e4mv.png)
☃️ Chemical formulae ➝
![\sf{Al_2(CO_3)_3}](https://img.qammunity.org/2021/formulas/chemistry/middle-school/66odm79oecg84fedp998j2du4c0206bbjs.png)
How to find?
For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.
![\boxed{ \sf{no. \: of \: moles = (given \: weight)/(molecular \: weight) }}](https://img.qammunity.org/2021/formulas/chemistry/middle-school/2dev18vrjpyyjvfy5rajcyvun55bxvynu4.png)
Solution:
❍ Molecular weight of
![\sf{Al_2(CO_3)_3}](https://img.qammunity.org/2021/formulas/chemistry/middle-school/66odm79oecg84fedp998j2du4c0206bbjs.png)
= 2 × 27 + 3 × 12 + 9 × 16
= 54 + 36 + 144
= 234
❍ Given weight: 10 g
Then, no. of moles,
⇛ No. of moles = 10 / 234
⇛ No. of moles = 0.0427 moles
⚘ No. of moles of Aluminium carbonate in the given weight = 0.0427 moles.
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