Question

Simplify the scalar multiplication on the matrix.

Answer 1

third option

Explanation:

Given

3
`\left[\begin{array}{ccc}-2&5\\1&0\\\end{array}\right]`

Multiply each element in the matrix by 3

=
`\left[\begin{array}{ccc}3(-2)&3(5)\\3(1)&3(0)\\\end{array}\right]`

=
`\left[\begin{array}{ccc}-6&15\\3&0\\\end{array}\right]`