Question

calculate the number of moles equivalent to 25.0 gram of copper II sulfate pentahydrate [CuSO4 5H2O]​

Answer 1

`\LARGE{ \boxed{ \blue{ \rm{Answer}}}}`

☃️ Chemical formulae ➝
`\sf{CuSO_4.5H_2O}`

How to find?

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

`\boxed{ \sf{No. \: of \: moles = (Given \: weight)/(Molecular \: weight) }}`

Solution:

Atomic weight of Elements:

• Cu = 64
• S = 32
• O = 16
• H = 1

❍ Molecular weight of
`\sf{CuSO_4.5H_2O}`

= 64 + 32 + (16 × 4) + 5(2 × 16)

= 96 + 64 + 90

= 250 g/mol

❍ Given weight: 25 g

Then, no. of moles,

⇛ No. of moles = 25 g/ 250 g mol‐¹

⇛ No. of moles = 0.1 moles

⚘ No. of moles of Copper Sulphate pentahydrate in the given weight = 0.1 moles.

━━━━━━━━━━━━━━━━━━━━

Answer 2

The answer is 0.1 mol

Step-by-step explanation:

To calculate the number of moles in the given substance we use the equation

`n = (m)/(M)`

where

n is the number of moles

M is the molar mass

m is the mass of the substance

To calculate the number of moles we must first find the molar mass

That's

M( CuSO4 5H2O )

Cu = 64 , S = 32 , O = 16 H = 1

So we have

M( CuSO4 5H2O ) = 64 + 32 + (16 × 4) +

5( 2 + 16)

M( CuSO4 5H2O ) = 96 + 64 + 5(18)

M( CuSO4 5H2O ) = 160 + 90

M( CuSO4 5H2O ) = 250 g/mol

M( CuSO4 5H2O ) = 250 g/mol

mass of CuSO4 5H2O = 25 g

Substitute the values into the above formula

That's

`n = (25g)/(250 \: g/mol)`

We have the final answer as

n = 0.1 mol

Hope this helps you