Question

A box contains12 balls in which 4 are white,3 blue and 5 are red.3 balls are drawn at random from the box.Find the chance that all three balls are of sifferent color.(answer in three decimal places)

Answer 1

0.273

Explanation:

Total number of balls is 4+3+5 = 12

There are 6 ways to draw 3 different colors (WBR, WRB, BWR, BRW, RWB, RBW) each with a chance of 4/12 · 3/11 · 5/10 = 1/22

So the total chance is 6 · 1/22 = 6/22 = 3/11 ≈ 0.273

Answer 2

`|\Omega|=_(12)C_3=(12!)/(3!9!)=(10\cdot11\cdot12)/(2\cdot3)=220\\|A|=4\cdot3\cdot5=60\\\\P(A)=(60)/(220)=(3)/(11)\approx0,273`