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If you're good at angles of depression please help meeeeee and show full working out tyyyyyyyyyy

If you're good at angles of depression please help meeeeee and show full working out-example-1

2 Answers

3 votes
what they said is definitely right
User Cristian Rennella
by
6.3k points
5 votes

Answer:

236.9 m

Explanation:

Let x and y represent the distances to the near and far cars, respectively. You know from the definition of the tangent of an angle that ...

tan(angle of depression) = building height/distance to car

tan(10°39') = 150/x

x = 150/tan(10°39')

and

tan(8°15') = 150/y

y = 150/tan(8°15')

The difference of these two distances is the distance between the cars:

y - x = 150/tan(8°15') -150/tan(10°39')

__

The minutes of arc can be converted to fractional degrees:

15' = 15'/(60'/1°) = (15/60)° = 0.25°

39' = 39'/(60'/1°) = (39/60)° = (13/20)° = 0.65°

So, the distance of interest is ...

distance between cars = (150 m)(1/tan(8.25°) -1/tan(10.65°)) ≈ 236.86 m

The cars are about 236.9 meters apart.

If you're good at angles of depression please help meeeeee and show full working out-example-1
User Joseph Salisbury
by
5.7k points