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In Exercise 4, find the surface area of the solid
formed by the net.

In Exercise 4, find the surface area of the solid formed by the net.-example-1
User Shikiryu
by
5.3k points

1 Answer

1 vote

Answer:

535.2 cm²

Explanation:

The surface area the solid formed by the net in exercise 4 can be calculated by finding the area of each part that makes up the net.

The net consists of 2 triangles and 3 rectangles.

Each triangle has a base (b) of 8 cm and a height (h) of = √(8² - 4²) (using Pythagorean theorem)

height = 6.9cm

Each rectangle has length (l) of 20cm, and width (w) of 8cm

Therefore, Surface Area (S.A) = area of 3 rectangles + area of 2 triangles

S.A = 3(l*b) + 2(½*b*h)

S.A = 3(20*8) + 2(½*8*6.9)

S.A = 3(160) + (1*8*6.9)

S.A = 480 + 55.2 = 535.2 cm²

User MeltedPenguin
by
5.5k points
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