Answer:
The measure of central tendency, mean and median are approximately equal for the boys indicating that the data of the boys is more evenly spread while standard deviation of the girls data is less than those of the boys indicating that the data for the girls is less widely spread.
Explanation:
The given data are;
, 1 2 3 4 5 6 7 8 9 10
Girls, 50 32 15 56 81 50 18 81 22 55
Boys, 75 41 25 22 7 0 43 12 45 70
Sorting the data gives;
Girls, 15, 18, 22, 32, 50, 50, 55, 56, 81, 81
Boys, 0, 7, 12, 22, 25, 41, 43, 45, 70, 75
For the even numbered sample data size, the first quartile, Q₁ is found by sharing the data into two and finding the median of the left half which gives;
10/2 = 5 on each half
The first quartile, Q₁, is the median of the left 5 data points which is the 3rd data point = 22 for girls and 12 for boys
The third quartile, Q₃, is found in similar method to be the 8th data point which is 56 for girls and 45 for boys
The median = 50 for girls and 33 for boys
Therefore, the interquartile ranges are;
IQR = 56 - 22 = 34 for girls, 45 - 12 = 33 for boys
We check for outliers.
Q₁ - 1.5×IQR = 22 - 1.5*34 = -29
Q₃ + 1.5×IQR = 56 + 1.5*34 = 107
We check the mean of both data samples as follows;
Average for the girls = 46
Average for the boys = 34
Standard deviation for girls = 23.99
Standard deviation for girls = 25.43
Therefore, the measure of central tendency is more accurate for the boys indicating that the data of the boys is more evenly spread while the data for the girls is less widely spread.