223k views
3 votes
25 point please help I would really appreciate it :)))

25 point please help I would really appreciate it :)))-example-1

1 Answer

4 votes

Answer:

(a) 40

(b) 15% per week, to the nearest percent.

Explanation:

Given:

old production,

P(w) = 230(1.1^w)

(a) At week 0, w=0, so

P(0) = 230(1.1^0) = 230

Difference (old - new) = 230-190 = 40

(b) about 15% per week

(c) from the 4th week on

approximate growth rate of new factory

N(w) = 190(R^w)

we know

w=0, N(0) = 190

w=7, N(7) = 505

so R=(505/190)^(1/7) = 1.1499 = 1.15 approx.

(c)

The old production tabulated:

w P(w) New

0 230 190

1 253 220

2 278 252

3 306 290

4 337 337

5 370 380

6 407 440

7 448 505

So we see that at the end of the 4th week, the two productions match, and new factory begins to exceed old production.

User Amorphous
by
6.0k points