Register
What would happen to the rate of a reaction with rate law rate = k [NO]2[Hz] if the concentration of NO were doubled?
116k views
0 votes
What would happen to the rate of a reaction with rate law rate = k [NO]2[Hz] if

the concentration of NO were doubled?

User Pindo
by
8.4k points

2 Answers

5 votes

Answer:

The rate would have doubled

Step-by-step explanation:

User Naser Nikzad
by
8.3k points
1 vote
The rate of a reaction with this rate law would increase by a factor of 4 if NO concentration were doubled.
User Javiel
by
8.3k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Other Questions

Compare and contrast an electric generator and a battery??
How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Why is gold preferred as a superior metal over silver and bronze?
Link Copied!