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The pH of 0.0001 M solution of Ca(OH)2 is

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Explanation:

Since Ca(OH)2 is Basic, we need to find pOH:

pOH = - log [OH-]

pOH = - log(0.0001)

pOH = - ( - 4)

pOH = 4

Since, pH + pOH = 14

Therefore,

pH of 0.0001M sol. of Ca(OH)2 = 10

User Edgar Quintero
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