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Evaluate −x^2−5 y^3 when x = 4 and y = 1
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4 votes
Evaluate −x^2−5 y^3 when x = 4 and y = 1

User Kekub
by
7.3k points

2 Answers

5 votes

Answer:

Simplify:


-4^2-5(1^3)

So you get:


-21\\

User Jeff Hykin
by
7.1k points
4 votes

Answer:


\huge\boxed{-21}

Explanation:

-x²-5y³

Given that x = 4, y = 1


-(4)^2-5(1)^3


-16-5(1)\\-16-5\\-21

User Madewulf
by
6.7k points
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