Question

Factor the polynomial: 11x− xy +11y−x2

Answer 1

(x - 11)(-x - y)

Explanation:

To factor the polynomial 11x - xy + 11y - x² completely, let's group the terms and factor them separately.

Rearranging the terms, we have:

11x - xy + 11y - x²

Let's rearrange the terms again to group similar terms together:

x² + 11x - xy + 11y

Now, we can factor out the common factor from each pair of terms:

x(-x + 11) - y(x - 11)

Simplifying further, we can factor out -1 from the first pair of terms:

-x(x - 11) - y(x - 11)

Now, notice that we have a common factor of (x - 11) in both terms. Factoring out this common factor, we obtain:

(x - 11)(-x - y)

Therefore, the polynomial 11x - xy + 11y - x² can be factored completely as (x - 11)(-x - y).

Answer 2

`11x- xy +11y-x^2=\\-x^2-xy+11x+11y=\\-x(x+y)+11(x+y)=\\-(x-11)(x+y)`