Question

Pls help A car starts from rest and gains a velocity of 20m/s in 10 seconds calculate its acceleration and the distance covered by it in this time

Answer 1

`\boxed{\sf Acceleration \ (a) = 2 \ m/s^(2)}`

`\boxed{\sf Distance \ covered \ (s) = 100 \ m}`

Given:

Initial velocity (u) = 0 m/s

Final velocity (v) = 20 m/s

Time taken (t) = 10 sec

To Find:

(i) Acceleration (a)

(ii) Distance covered (s)

Step-by-step explanation:

`\sf (i) \ From \ 1^(st) \ equation \ of \ motion:`

`\sf \implies v = u + at`

`\sf \implies 20 = 0 + a(10)`

`\sf \implies 10a = 20`

`\sf \implies (10a)/(10) = (20)/(10)`

`\sf \implies a = 2 \: m/ {s}^(2)`

`\sf (ii) \ From \ 2^(nd) \ equation \ of \ motion:`

`\sf \implies s = ut + (1)/(2) a {t}^(2)`

`\sf \implies s = (0)(10) + (1)/(2) * 2 * {(10)}^(2)`

`\sf \implies s = \frac{1}{ \cancel{2}} * \cancel{2} * {(10)}^(2)`

`\sf \implies s = {10}^(2)`

`\sf \implies s = 100 \: m`