Answer:
(B) has the closest values.
Explanation:
Solve the triangle: A = 51°, b = 14, c = 6
A. a ≈ 14.9, C ≈ 28.1, B ≈ 100.9
B. a ≈ 11.2, C ≈ 24.1, B ≈ 104.9
C. a ≈ 14.9, C ≈ 24.1, B ≈ 104.9
Using the cosine rule,
a^2 = b^2+c^2-2bc (cos(A))
= 196+36 - 2(14)(6)cos(51)
= 196+36 - 105.72
= 126.27
a = sqrt(126.27)
= 11.24
using sine rule,
sin(C)/sin(A) = 6/11.24
sin(C) = 6/11.24*sin(51)= 0.41495
C = arcsin(0.41495 = 24.5 degrees, reasonably close to the given value, probably due to the answer used the rounded value of a.
B = 180-51-24.5 =104.5
Out of the given options, only (B) has the correct value of a and C