Answer:
The distance is
![y = 0.00162 \ m](https://img.qammunity.org/2021/formulas/physics/college/76dd0yl4988c7rvcakz2mbayqswwgtp0sm.png)
Step-by-step explanation:
From the question we are told that
The wavelength is
![\lambda = 486 \ nm = 486 *10^(-9) \ m](https://img.qammunity.org/2021/formulas/physics/college/ikl73r2h5rb4mcvgc5kkzfj36836x0dezi.png)
The slit spacing is
![d = 0.600 \ mm = 0.60 *10^(-3) \ m](https://img.qammunity.org/2021/formulas/physics/college/9o778tinuhn1ffaakc2h4t6m9wmsankg8j.png)
The distance of the screen is
![D = 2.0 \ m](https://img.qammunity.org/2021/formulas/physics/college/d26jmoz3nyspwjcpojv50bnvvv989kfb5t.png)
Generally the distance along the screen between adjacent bright fringes is mathematically represented as
![y = (\lambda * D)/(d)](https://img.qammunity.org/2021/formulas/physics/college/11ezexpz17jwp61ma8izku0o0i562vsqxt.png)
substituting values
![y = ( 486 *10^(-9) * 2)/(0.6*10^(-3))](https://img.qammunity.org/2021/formulas/physics/college/hbfyc9kdpbkg8njgptugtqoomg0insoobu.png)
![y = 0.00162 \ m](https://img.qammunity.org/2021/formulas/physics/college/76dd0yl4988c7rvcakz2mbayqswwgtp0sm.png)