Question

6. What is the bulk modulus of oxygen if 32.0 g of oxygen occupies 22.4 L and the speed of sound in the oxygen is 317 m/s?

Answer 1

`\boxed{\sf Bulk \ modulus \ of \ oxygen \approx 143.5 \ kPa}`

Given:

Mass of oxygen (m) = 32.0 g = 0.032 kg

Volume occupied by oxygen (V) = 22.4 L = 0.0224 m³

Speed of sound in oxygen (v) = 317 m/s

To Find:

Bulk modulus of oxygen

Step-by-step explanation:

`\sf Density \ of \ oxygen \ (\rho) = (m)/(V)`

`\sf \implies Bulk \ modulus \ of \ oxygen \ (B) = v^(2) \rho`

`\sf \implies B = v^(2) *(m)/(V)`

`\sf \implies B = {(317)}^(2) * (0.032)/(0.0224)`

`\sf \implies B = {(317)}^(2) * 1.428`

`\sf \implies B = 100489 * 1.428`

`\sf \implies B = 143498.292 \: Pa`

`\sf \implies B \approx 143.5 \: kPa`