Question

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $65 . For one performance, 25 advance tickets and 35 same-day tickets were sold. The total amount paid for the tickets was 1875 . What was the price of each kind of ticket?

Answer 1

Answer: same day = 25

advanced = 40

Answer 2

same day = 25

advanced = 40

Explanation:

Let a = advanced tickets

s = same day tickets

s+a = 65

25a+35s = 1875

Multiply the first equation by -25

-25s -25a = -1625

Add this to the second equation

25a+35s = 1875

-25a -25s= -1625

---------------------------

10s = 250

Divide each side by 10

10s/10 = 250/10

s =25

Now find a

s+a = 65

25+a = 65

a = 40