Question

If an electron is accelerated from rest through a potential difference of 1.60 x 102V, what is its de Broglie wavelength

Answer 1

0.09 x10^-10m

Step-by-step explanation:

Using wavelength=( 12.27 A)/√V

= 12.27 x 10^-10/ √1.6x10^2

= 0.09x10^-10m