Question

A planar electromagnetic wave is propagating in the +x direction. At a certain point P and at a given instant, the electric field of the wave is given by = (0.082 V/m) . What is the magnetic vector of the wave at the point P at that instant? (c = 3.0 × 108 m/s)

Answer 1

`B=2.74* 10^(-10)\ T`

Step-by-step explanation:

It is given that,

A planar electromagnetic wave is propagating in the +x direction.The electric field at a certain point is, E = 0.082 V/m

We need to find the magnetic vector of the wave at the point P at that instant.

The relation between electric field and magnetic field is given by :

`c=(E)/(B)`

c is speed of light

B is magnetic field

`B=(E)/(c)\\\\B=(0.082)/(3* 10^8)\\\\B=2.74* 10^(-10)\ T`

So, the magnetic vector at point P at that instant is
`2.74* 10^(-10)\ T`.