115k views
2 votes
If (ax+b)(x-3) = 4x^2+cx-9 for all values of x, what is the value of c? a) -9 b) -6 c) 6 d) 9

User SunnyShah
by
7.7k points

1 Answer

4 votes

Answer:

c=-9

Explanation:

Hello,


(ax+b)(x-3)=ax(x-3)+b(x-3)=ax^2-3ax+bx-3b\\\\=ax^2+(b-3a)x+(-3b) \\\\\text{And it should be equal to } 4x^2+cx-9

We can identify the like terms so:

a = 4

b-3a = c

3b = 9 <=> b = 3

So c = 3 - 3*4 = 3-12 = -9

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

User James Poag
by
6.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.