Find the missing factor D that makes the equality true -15y^4=(D)(3y^2)

Question

asked Nov 3, 2021 197k views

1 Answer

Louisbros · Answer 1 · 2021-11-10T06:53:48+0000

Answer:

D=-5y^2

Explanation:

We have the equation:

$\displaystyle -15y^4=D(3y^2)$

And we want to find D such that the equation is true.

So, we can divide both sides by 3y². This will yield:

$\displaystyle D=(-15y^4)/(3y^2)$

We can split this into:

$\displaystyle D=(-15)/(3)\cdot(y^4)/(y^2)$

Simplify. Hence:

D=-5y^2