Question

Find the missing factor D that makes the equality true -15y^4=(D)(3y^2)

Answer 1

`D=-5y^2`

Explanation:

We have the equation:

`\displaystyle -15y^4=D(3y^2)`

And we want to find D such that the equation is true.

So, we can divide both sides by 3y². This will yield:

`\displaystyle D=(-15y^4)/(3y^2)`

We can split this into:

`\displaystyle D=(-15)/(3)\cdot(y^4)/(y^2)`

Simplify. Hence:

`D=-5y^2`