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If x^2 -8x=48 and x<0, what is the value of x+10?

User Flypig
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2 Answers

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x^2 -8x - 48 = 0
(x-12)(x+4) = 0
x=12, x=-4
Since x<0, x must be -4
Therefore, -4+10=6
User Crunkchitis
by
7.9k points
2 votes

Answer:

6

Explanation:

To calculate x+10, we first need to find x. To do this, we can use the first equation.

We are given the equation:


x^2-8x=48

To solve for x, turn one side of the equation into 0 and solve. Therefore:


x^2-8x=48\\x^2-8x-48=0\\(x-12)(x+4)=0\\x=-4, 12

So, the possible values for x are -4 and 12.

However, we are also told that x<0. In other words, x must be negative. Thus, we can remove 12. That leaves us with: x=-4.

So:


x+10\\(-4)+10\\=6

User Vrinda
by
8.8k points

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