Answer:

Step-by-step explanation:
From the question we are told that
The distance of the screen is

The distance of separation of the slit is

The wavelength of light is

Generally the condition for constructive interference is

=>
![\theta = sin^(-1) [ ( n * \lambda )/(d ) ]](https://img.qammunity.org/2021/formulas/physics/college/2bt7wxuwfyk9f3t9iihoy6cvgd9bnuv8tr.png)
here n = 1 because we are considering the central diffraction peak
=>
![\theta = sin^(-1) [ ( 1 * 588*10^(-9) )/(0.0328*10^(-3) ) ]](https://img.qammunity.org/2021/formulas/physics/college/dfzex8sza3lorzkusntsol37sd6f4v49hv.png)
=>

Generally the width of central diffraction peak on a screen is mathematically evaluated as

substituting values

