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The rate at which an assembly line workers efficiency E (expressed as a percent) changes with respect to time t is given by E'(t) = 75 - 6t, where t is the number of hours since the workers shift began. Assuming that E(1) = 92, find E(t).

User Sarumont
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1 Answer

3 votes

By the fundamental theorem of calculus,


E(t)=E(1)+\displaystyle\int_1^t E'(u)\,\mathrm du

So we have


E(t)=92+\displaystyle\int_1^t(75-6u)\,\mathrm du


E(t)=92+(75u-3u^2)\bigg|_1^t


E(t)=20 + 75 t - 3 t^2

User Glen Little
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