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1 vote
Solve logs (8 - 3x) = log20 for x.
A. X = 14
B. X = -13
C.x = -8
D. X= -4

2 Answers

4 votes

Answer:


\boxed{\sf x = -4}

Explanation:


\sf Solve \: for \: x \: over \: the \: r eal \: numbers:


\sf \implies log(8 - 3x) = log 20


\sf Cancel \: logarithms \: by \: taking \: exp \: of \: both \: sides:


\sf \implies 8 - 3x = 20


\sf Subtract \: 8 \: from \: both \: sides:


\sf \implies 8 - 3x - 8 = 20 - 8


\sf \implies - 3x = 12


\sf Divide \: both \: sides \: by \: - 3:


\sf \implies (-3x)/(-3) = (12)/(-3)


\sf \implies x = - 4

User Shoe
by
8.1k points
4 votes

Answer:

x = -4

Explanation:

logs (8 - 3x) = log20

Since we are taking the log on each side

log a = log b then a = b

8 -3x = 20

Subtract 8 from each side

8 -3x-8 =20 -8

-3x = 12

Divide by -3

-3x/-3 = 12/-3

x = -4

User Irudaya Rajasekar
by
8.6k points

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