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Experiments are performed with ultracold neutrons having velocities of 7.54 m/s. (a) What is the wavelength (in nm) of such a neutron

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Answer:

λ = 52.5 nm

Step-by-step explanation:

De Broglie's duality principle states that all matter has wave and particle characteristics, being related by the expression

p = h / λ

where the moment

p = mv

λ = h / mv

let's calculate

λ = 6.63 10⁻³⁴ / 1.675 10⁻²⁷ 7.54

λ = 5.25 10⁻⁸ m

Let's reduce anm

λ = 5.25 10⁻⁸ m (10⁹ nm / 1m)

λ = 52.5 nm

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