Question

Given y(x) = f(x)g(x). Find the slope of the tangent line to y(x) at x = 7.​

Answer 1

Explanation:

Interesting problem.

At 6<x<8,

f(x) = x-7

at 5<x<8

g(x) = (15-x)/2

=>

y(x)

= f(x)*g(x)

= (x-7)(15-x)/2

= (x^2+22x-105)/2

differentiate y(x) with respect to x,

y'(x) = -x+11

at x = 7,

y'(7) = -(7) + 11 = 4