Answer:
a = 15/2, b = 2/5
Explanation:
For a system of two linear equations to have infinitely many solutions, the equations must be equivalent to one another.
Assuming a and b to be constants, and since b is absent from equations, there must be a typo where b was mistaken for a 6.
Modified equations:
2a - 15x + 3y - 5 = 0 ...................(1)
3x + (b - 1)y - 2 = 0 .....................(2)
rearrange equations to standard form:
-15x + 3y + 2a-5 = 0 .................(1a)
3x + (b-1)y -2 = 0 ........................(2)
To equalize the coefficient of x, multiply (2) by -5
-15x - 5(b-1) y +10 = 0 ................(2a)
Subtract (2a) from (1a)
3y + 5(b-1)y + 2a-5 -10 = 0 ..............(3)
For the two equations (1a) and (2a) to be identical, coeffients of y and constant term of (3) must equal zero.
3+5(b-1) = 0 .................(4)
3+5b-5 = 0
5b = 2
b = 2/5
2a-5-10 = 0 .....................(5)
a = 15/2