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What is the distance between the points (4 3) and (1 -1) on the cordinate plane

User Dave Long
by
5.7k points

2 Answers

4 votes

Answer:

5

Explanation:

distance = square root of (1-4)^2 + (-1-3)^2

=> distance = square root of -3^2 + (-4)^2

=> distance = square root of 9 + 16

=> distance = square root of 25

=> distance = 5

User Nymphadora
by
5.2k points
2 votes

Answer:

d = 5

Explanation:

Distance formula:
d=√((x_2-x_1)^2+(y_2-y_1)^2)

d = sqrt[(1-4)^2+(-1-3)^2]

d = 5

User MrM
by
5.0k points