24.5k views
0 votes
The vertex formation of a parabola is x = 8(y- 1)2-76.

What is the standard form of the equation?

User Lbatson
by
7.9k points

2 Answers

2 votes
The answer to this question is x = 8y^2 - 16y -68
User Jesse De Wit
by
9.5k points
4 votes

Answer:


\boxed{x=8y^2-16y-68}

Explanation:

Hello, please consider the following.


x=8(y- 1)^2-76\\\\x=8(y^2-2y+1)-76\\\\x=8y^2-16y+8-76\\\\\boxed{x=8y^2-16y-68}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

User Strongopinions
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.