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Find the vertex of f(x)= x^2+ 6x + 36


Pls help soon

User Pynexj
by
4.5k points

1 Answer

6 votes

Answer:

vertex(-3,27)

Explanation:

f(x)= x^2+ 6x + 36 ( a=1,b=6,c=36)

V(h,k)

h=-b/2a=-6/2=-3

k=f(-3)=3²+6(-3)+36

f(-3)=9-18+36=27

vertex(-3,27)

User Balkana
by
4.7k points