Find the vertex of f(x)= x^2+ 6x + 36 Pls help soon

Question

asked Jan 13, 2021 189k views

1 Answer

Balkana · Answer 1 · 2021-01-20T09:24:03+0000

Answer:

vertex(-3,27)

Explanation:

f(x)= x^2+ 6x + 36 ( a=1,b=6,c=36)

V(h,k)

h=-b/2a=-6/2=-3

k=f(-3)=3²+6(-3)+36

f(-3)=9-18+36=27

vertex(-3,27)