The given question is incomplete, the complete question is:
An atom of 122In has a mass of 121.910280 amu. Calculate the binding energy in MeV per atom. Use the masses: mass of 1H atom = 1.007825 amu mass of a neutron = 1.008665 amu 1 amu = 931.5 MeV
Answer:
The correct answer is 1029.95 MeV.
Step-by-step explanation:
Based on the given information,
The mass of proton is 1.007825, the mass of neutron is 1.008665.
The atomic number of Indium is 49, therefore, the number of neutrons will be, 122-49 = 73.
Now the calculated mass will be,
= 49 * 1.007825 + 73 * 1.008665
= 49.383425 + 73.632545
= 123.01597
The mass defect is calculated by subtracting the actual mas from calculated mass,
Mass defect = Actual mass - Calculated mass
= 121.910280 - 123.01597
= -1.10569 amu
Now the binding energy will be,
Binding energy = 1.10569 * 931.5 MeV
= 1029.95 MeV