Answer:
Explanation:
Let A= probability it rains
P(A)=0.2
Let B be the probability that the train is late = 0.05
P(B)=0.05
A and B is A∩B= the probability it rains and the bus is late =0.01
probability pf (A and B)=0.01
7) independent events are related by expression:
A∩B=P(A)*P(B)
=0.2*0.05=0.01
check :
p(A|B)=P(A∩B)÷P(B)=0.01/0.05= 0.2
the two event are independent