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Find the​ mean, variance, and standard deviation of the binomial distribution with the given values of n and p. ​, The​ mean, ​, is nothing. ​(Round to the nearest tenth as​ needed.)

User Rosemary
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Complete Question

Find the​ mean, variance, and standard deviation of the binomial distribution with the given values of n and p. ​, The​ mean, ​, is nothing. ​(Round to the nearest tenth as​ needed.)

p = 0.6 n = 18

Answer:

The mean
\mu = 10.5

The standard deviation
\sigma = 2.08

The variance
var = 4.32

Explanation:

From the question we are told that

The probability of success is
p = 0.6

The sample size is
n = 18

Generally given that the distribution is binomial, then the probability of failure is mathematically represented as


q = 1- p

substituting values


q = 1- 0.6


q =0.4

Generally the mean is mathematically evaluated as


\mu = np

substituting values


\mu = 18 * 0.6


\mu = 10.5

The standard deviation is evaluated as


\sigma = √(npq)

substituting values


\sigma = √(18 * 0.6 * 0.4)


\sigma = 2.08

The variance is evaluated as


var = \sigma^2

substituting value


var = 2.08^2


var = 4.32

User Lillialexis
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