Question

A fish jumps out of the water at a speed of 12 feet per second. The height y (in feet) of the fish above the surface of the water is represented by the equation y=-16x^2+12x, where x is the time (in seconds) since the jump began. The fish reaches its highest point above the surface of the water after 0.375 seconds. How far above the surface is the fish at this time?

Answer 1

The fish is 2.25 ft above the surface at 0.375 seconds

Explanation:

Given:

y=-16x^2+12x

x=0.375 seconds

Substitute x=0.375 into the equation

y=-16x^2+12x

= -16(0.375)^2 +12(0.375

= -16(0.140625) + 4.5

= -2.25 + 4.5

= 2.25

y=2.25 ft

The fish is 2.25 ft above the surface at 0.375 seconds