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I know how to do it but right now I'm cooking and have no time please say if the first part is right and the second part will be much appreciated!

I know how to do it but right now I'm cooking and have no time please say if the first-example-1
User Rob Moll
by
8.2k points

2 Answers

1 vote

Answer:

Below

Explanation:

As we see the area is expressed as second degree polynomial

We have already a side wich is (x+15)

● x^2 +18x + 45 = w × (x+15)

● w = (x^2 +18x+45)/(x+15)

Using the eucledian division we get:

● w = x+3

Since x^2 +18x +45 = (x+15) × (x+3)

So your answer was right

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Let's calculate the dimensions if x= 8 yards

● the length

x+15 = 8+15 = 23 yards

● the width

x+3 = 8 + 3 = 11 yards

● the area

(x+15)×(x+3) = 23 × 11 = 253 yards^2

User Chiragkumar Thakar
by
8.8k points
6 votes

Part A is correct. We have x+15 as the length and x+3 as the width. Convention usually has the width be the smaller of the two.

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Part B will have you replace x with 8 and simplify

length = x+15 = 8+15 = 23

width = x+3 = 8+3 = 11

the rectangle is 23 yards by 11 yards, so the area is 23*11 = 253 square yards

User Shawntel
by
7.8k points

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