Question

Solve for m. √m-7 = n+3 It is worth like 40 points

Answer 1

sqrt of (m-7) = n+3

m = (n+3)^2 + 7 or m= n^2 + 6n + 16

sqrt of (m)-7 = n+3

m = (n+10)^2 or m =n^2 + 20n + 100

Explanation:

(2) move the constants to the other side, and square

or (1) square and move constants

then you can solve for m

Answer 2

`n^2+6n+16`

Explanation:

I'm going to assume you meant
`√(m-7) = n+3`, not
`√(m) - 7 = n+3`.

`(√(m-7)) ^2 = (n+3)^2\\\\(√(m-7)^2) = (n+3)^2\\\\(m-7)^{(2)/(2) } = (n+3)^2\\\\m - 7 = (n+3)^2\\\\m - 7 = n^2 + 2n\cdot3 + 3^2\\\\m - 7 = n^2 + 6n + 9\\\\m - 7 + 7 = n^2 + 6n + 9 + 7\\\\m = n^2 + 6n + 16`

Hope this helped!